BUUCTF-web EasySearch (服务端包含注入ssi)

2020年6月3日 796次阅读共1249个字 0条评论 0人点赞 remon535

一打开就是登录页面

存在index.php.swp。。。（反正我是没有扫出来，题目没给提示），分析一波源码

<?php
        ob_start();
        function get_hash(){
                $chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789!@#$%^&*()+-';
                $random = $chars[mt_rand(0,73)].$chars[mt_rand(0,73)].$chars[mt_rand(0,73)].$chars[mt_rand(0,73)].$chars[mt_rand(0,73)];//Random 5 times
                $content = uniqid().$random;
                return sha1($content); 
        }
    header("Content-Type: text/html;charset=utf-8");
        ***
    if(isset($_POST['username']) and $_POST['username'] != '' )
    {
        $admin = '6d0bc1';
        if ( $admin == substr(md5($_POST['password']),0,6)) {
            echo "<script>alert('[+] Welcome to manage system')</script>";
            $file_shtml = "public/".get_hash().".shtml";
            $shtml = fopen($file_shtml, "w") or die("Unable to open file!");
            $text = '
            ***
            ***
            <h1>Hello,'.$_POST['username'].'</h1>
            ***
                        ***';
            fwrite($shtml,$text);
            fclose($shtml);
            ***
                        echo "[!] Header  error ...";
        } else {
            echo "<script>alert('[!] Failed')</script>";

    }else
    {
        ***
    }
        ***
?>

只要密码的md5的前六位等于'6d0bc1'就能成功登陆
构造爆破脚本

#!/usr/bin/python
import hashlib
a="6d0bc1"
password="0123456789"
for i in range(10000000):
   c=hashlib.md5(str(i)).hexdigest()
   if c[0:6]==a:
    print (i)